2v^2-4v=-5

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Solution for 2v^2-4v=-5 equation:


Simplifying
2v2 + -4v = -5

Reorder the terms:
-4v + 2v2 = -5

Solving
-4v + 2v2 = -5

Solving for variable 'v'.

Reorder the terms:
5 + -4v + 2v2 = -5 + 5

Combine like terms: -5 + 5 = 0
5 + -4v + 2v2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
2.5 + -2v + v2 = 0

Move the constant term to the right:

Add '-2.5' to each side of the equation.
2.5 + -2v + -2.5 + v2 = 0 + -2.5

Reorder the terms:
2.5 + -2.5 + -2v + v2 = 0 + -2.5

Combine like terms: 2.5 + -2.5 = 0.0
0.0 + -2v + v2 = 0 + -2.5
-2v + v2 = 0 + -2.5

Combine like terms: 0 + -2.5 = -2.5
-2v + v2 = -2.5

The v term is -2v.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2v + 1 + v2 = -2.5 + 1

Reorder the terms:
1 + -2v + v2 = -2.5 + 1

Combine like terms: -2.5 + 1 = -1.5
1 + -2v + v2 = -1.5

Factor a perfect square on the left side:
(v + -1)(v + -1) = -1.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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